Base | Representation |
---|---|
bin | 1010011110101000001100… |
… | …1011011110101011110010 |
3 | 1111210102111102102122000011 |
4 | 2213222003023132223302 |
5 | 3002231112044044214 |
6 | 40300451422245134 |
7 | 2266246426422343 |
oct | 247520313365362 |
9 | 44712442378004 |
10 | 11521303112434 |
11 | 374218027a055 |
12 | 1360aa51267aa |
13 | 6575b9c042ab |
14 | 2bb8c3b720ca |
15 | 14ea67660ac4 |
hex | a7a832deaf2 |
11521303112434 has 4 divisors (see below), whose sum is σ = 17281954668654. Its totient is φ = 5760651556216.
The previous prime is 11521303112411. The next prime is 11521303112443. The reversal of 11521303112434 is 43421130312511.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6779592175225 + 4741710937209 = 2603765^2 + 2177547^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11521303112396 and 11521303112405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2880325778107 + ... + 2880325778110.
Almost surely, 211521303112434 is an apocalyptic number.
11521303112434 is a deficient number, since it is larger than the sum of its proper divisors (5760651556220).
11521303112434 is an equidigital number, since it uses as much as digits as its factorization.
11521303112434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5760651556219.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 11521303112434 its reverse (43421130312511), we get a palindrome (54942433424945).
The spelling of 11521303112434 in words is "eleven trillion, five hundred twenty-one billion, three hundred three million, one hundred twelve thousand, four hundred thirty-four".
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