115214131 has 2 divisors, whose sum is σ = 115214132. Its totient is φ = 115214130.

The previous prime is 115214093. The next prime is 115214137. The reversal of 115214131 is 131412511.

It is a strong prime.

It is an emirp because it is prime and its reverse (131412511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115214131 - 2¹³ = 115205939 is a prime.

It is a super-2 number, since 2×115214131² = 26548591964170322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115214099 and 115214108.

It is not a weakly prime, because it can be changed into another prime (115214137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57607065 + 57607066.

It is an arithmetic number, because the mean of its divisors is an integer number (57607066).

Almost surely, 2^115214131 is an apocalyptic number.

115214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

115214131 is an equidigital number, since it uses as much as digits as its factorization.

115214131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 19.

The square root of 115214131 is about 10733.7845609086. The cubic root of 115214131 is about 486.5960541094.

Adding to 115214131 its reverse (131412511), we get a palindrome (246626642).

The spelling of 115214131 in words is "one hundred fifteen million, two hundred fourteen thousand, one hundred thirty-one".