Base | Representation |
---|---|
bin | 1010011110101001100000… |
… | …1010011011000100010011 |
3 | 1111210110101221212100101012 |
4 | 2213222120022123010103 |
5 | 3002232322210011021 |
6 | 40300550400001135 |
7 | 2266261232643356 |
oct | 247523012330423 |
9 | 44713357770335 |
10 | 11521655157011 |
11 | 3742340a7038a |
12 | 1360b830001ab |
13 | 657644b24cac |
14 | 2bb91881229d |
15 | 14ea8850035b |
hex | a7a9829b113 |
11521655157011 has 2 divisors, whose sum is σ = 11521655157012. Its totient is φ = 11521655157010.
The previous prime is 11521655156971. The next prime is 11521655157031. The reversal of 11521655157011 is 11075155612511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11521655157011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11521655157011.
It is not a weakly prime, because it can be changed into another prime (11521655157031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760827578505 + 5760827578506.
It is an arithmetic number, because the mean of its divisors is an integer number (5760827578506).
Almost surely, 211521655157011 is an apocalyptic number.
11521655157011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11521655157011 is an equidigital number, since it uses as much as digits as its factorization.
11521655157011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52500, while the sum is 41.
The spelling of 11521655157011 in words is "eleven trillion, five hundred twenty-one billion, six hundred fifty-five million, one hundred fifty-seven thousand, eleven".
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