1152220463143 has 4 divisors (see below), whose sum is σ = 1158880697208. Its totient is φ = 1145560229080.

The previous prime is 1152220463123. The next prime is 1152220463183. The reversal of 1152220463143 is 3413640222511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1152220463143 - 2¹³ = 1152220454951 is a prime.

It is a super-4 number, since 4×1152220463143⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1152220463099 and 1152220463108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1152220463113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3330116773 + ... + 3330117118.

It is an arithmetic number, because the mean of its divisors is an integer number (289720174302).

Almost surely, 2^{1152220463143} is an apocalyptic number.

1152220463143 is a deficient number, since it is larger than the sum of its proper divisors (6660234065).

1152220463143 is an equidigital number, since it uses as much as digits as its factorization.

1152220463143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6660234064.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 1152220463143 its reverse (3413640222511), we get a palindrome (4565860685654).

The spelling of 1152220463143 in words is "one trillion, one hundred fifty-two billion, two hundred twenty million, four hundred sixty-three thousand, one hundred forty-three".