Base | Representation |
---|---|
bin | 10000110001001010111… |
… | …001110110111011000011 |
3 | 11002011022022122020120212 |
4 | 100301022321312323003 |
5 | 122334411311311413 |
6 | 2241210221424335 |
7 | 146152156452533 |
oct | 20611271667303 |
9 | 4064268566525 |
10 | 1152307916483 |
11 | 404766861939 |
12 | 1673a970b0ab |
13 | 8487ba32549 |
14 | 3dab45274c3 |
15 | 1ee92c7cca8 |
hex | 10c4ae76ec3 |
1152307916483 has 2 divisors, whose sum is σ = 1152307916484. Its totient is φ = 1152307916482.
The previous prime is 1152307916477. The next prime is 1152307916491. The reversal of 1152307916483 is 3846197032511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1152307916483 - 24 = 1152307916467 is a prime.
It is not a weakly prime, because it can be changed into another prime (1152307916413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576153958241 + 576153958242.
It is an arithmetic number, because the mean of its divisors is an integer number (576153958242).
It is a 1-persistent number, because it is pandigital, but 2⋅1152307916483 = 2304615832966 is not.
Almost surely, 21152307916483 is an apocalyptic number.
1152307916483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152307916483 is an equidigital number, since it uses as much as digits as its factorization.
1152307916483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 1152307916483 in words is "one trillion, one hundred fifty-two billion, three hundred seven million, nine hundred sixteen thousand, four hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •