Base | Representation |
---|---|
bin | 11010001100110101100001… |
… | …010111110101101010011011 |
3 | 120010000000011012112112211022 |
4 | 122030311201113311222123 |
5 | 110100422211133122301 |
6 | 1045024311130353055 |
7 | 33162121212321533 |
oct | 3214654127655233 |
9 | 503000135475738 |
10 | 115231311223451 |
11 | 33797363125525 |
12 | 10b10724b8b78b |
13 | 4c3b35c5b4337 |
14 | 20653220164c3 |
15 | d4c66e18cd1b |
hex | 68cd615f5a9b |
115231311223451 has 2 divisors, whose sum is σ = 115231311223452. Its totient is φ = 115231311223450.
The previous prime is 115231311223381. The next prime is 115231311223471. The reversal of 115231311223451 is 154322113132511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115231311223451 is a prime.
It is not a weakly prime, because it can be changed into another prime (115231311223471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615655611725 + 57615655611726.
It is an arithmetic number, because the mean of its divisors is an integer number (57615655611726).
Almost surely, 2115231311223451 is an apocalyptic number.
115231311223451 is a deficient number, since it is larger than the sum of its proper divisors (1).
115231311223451 is an equidigital number, since it uses as much as digits as its factorization.
115231311223451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21600, while the sum is 35.
Adding to 115231311223451 its reverse (154322113132511), we get a palindrome (269553424355962).
The spelling of 115231311223451 in words is "one hundred fifteen trillion, two hundred thirty-one billion, three hundred eleven million, two hundred twenty-three thousand, four hundred fifty-one".
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