Base | Representation |
---|---|
bin | 11010001100110101100111… |
… | …110111010001000000111001 |
3 | 120010000000102210110022222221 |
4 | 122030311213313101000321 |
5 | 110100422422023001431 |
6 | 1045024330020444041 |
7 | 33162124004060500 |
oct | 3214654767210071 |
9 | 503000383408887 |
10 | 115231420125241 |
11 | 33797409647002 |
12 | 10b10755549621 |
13 | 4c3b379023874 |
14 | 2065332683837 |
15 | d4c678a00111 |
hex | 68cd67dd1039 |
115231420125241 has 24 divisors (see below), whose sum is σ = 141152291443680. Its totient is φ = 93536501067072.
The previous prime is 115231420125193. The next prime is 115231420125257. The reversal of 115231420125241 is 142521024132511.
It is not a de Polignac number, because 115231420125241 - 217 = 115231419994169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115231420125197 and 115231420125206.
It is not an unprimeable number, because it can be changed into a prime (115231420125641) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20568036 + ... + 25563781.
It is an arithmetic number, because the mean of its divisors is an integer number (5881345476820).
Almost surely, 2115231420125241 is an apocalyptic number.
It is an amenable number.
115231420125241 is a deficient number, since it is larger than the sum of its proper divisors (25920871318439).
115231420125241 is a wasteful number, since it uses less digits than its factorization.
115231420125241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46134533 (or 46134526 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 115231420125241 its reverse (142521024132511), we get a palindrome (257752444257752).
The spelling of 115231420125241 in words is "one hundred fifteen trillion, two hundred thirty-one billion, four hundred twenty million, one hundred twenty-five thousand, two hundred forty-one".
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