115231420125301 has 4 divisors (see below), whose sum is σ = 115237771431552. Its totient is φ = 115225068819052.

The previous prime is 115231420125257. The next prime is 115231420125313. The reversal of 115231420125301 is 103521024132511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115231420125301 - 2¹⁵ = 115231420092533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115231420125401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3175625911 + ... + 3175662196.

It is an arithmetic number, because the mean of its divisors is an integer number (28809442857888).

Almost surely, 2^{115231420125301} is an apocalyptic number.

It is an amenable number.

115231420125301 is a deficient number, since it is larger than the sum of its proper divisors (6351306251).

115231420125301 is an equidigital number, since it uses as much as digits as its factorization.

115231420125301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6351306250.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 115231420125301 its reverse (103521024132511), we get a palindrome (218752444257812).

The spelling of 115231420125301 in words is "one hundred fifteen trillion, two hundred thirty-one billion, four hundred twenty million, one hundred twenty-five thousand, three hundred one".