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115231420125313 is a prime number
BaseRepresentation
bin11010001100110101100111…
…110111010001000010000001
3120010000000102210110100002121
4122030311213313101002001
5110100422422023002223
61045024330020444241
733162124004060632
oct3214654767210201
9503000383410077
10115231420125313
1133797409647068
1210b10755549681
134c3b3790238cb
142065332683889
15d4c678a0015d
hex68cd67dd1081

115231420125313 has 2 divisors, whose sum is σ = 115231420125314. Its totient is φ = 115231420125312.

The previous prime is 115231420125257. The next prime is 115231420125373. The reversal of 115231420125313 is 313521024132511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110887997333569 + 4343422791744 = 10530337^2 + 2084088^2 .

It is a cyclic number.

It is not a de Polignac number, because 115231420125313 - 221 = 115231418028161 is a prime.

It is not a weakly prime, because it can be changed into another prime (115231420125373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615710062656 + 57615710062657.

It is an arithmetic number, because the mean of its divisors is an integer number (57615710062657).

Almost surely, 2115231420125313 is an apocalyptic number.

It is an amenable number.

115231420125313 is a deficient number, since it is larger than the sum of its proper divisors (1).

115231420125313 is an equidigital number, since it uses as much as digits as its factorization.

115231420125313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 115231420125313 its reverse (313521024132511), we get a palindrome (428752444257824).

The spelling of 115231420125313 in words is "one hundred fifteen trillion, two hundred thirty-one billion, four hundred twenty million, one hundred twenty-five thousand, three hundred thirteen".