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115232463894161 is a prime number
BaseRepresentation
bin11010001100110110100110…
…000100111011011010010001
3120010000010010112111021210002
4122030312212010323122101
5110100432041224103121
61045025021344215345
733162161610004535
oct3214664604733221
9503003115437702
10115232463894161
11337978a4845049
1210b109a700a555
134c3b4b4346c03
1420653d1145bc5
15d4c6da479e0b
hex68cda613b691

115232463894161 has 2 divisors, whose sum is σ = 115232463894162. Its totient is φ = 115232463894160.

The previous prime is 115232463894131. The next prime is 115232463894167. The reversal of 115232463894161 is 161498364232511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83127548039761 + 32104915854400 = 9117431^2 + 5666120^2 .

It is a cyclic number.

It is not a de Polignac number, because 115232463894161 - 218 = 115232463632017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115232463894097 and 115232463894106.

It is not a weakly prime, because it can be changed into another prime (115232463894167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57616231947080 + 57616231947081.

It is an arithmetic number, because the mean of its divisors is an integer number (57616231947081).

Almost surely, 2115232463894161 is an apocalyptic number.

It is an amenable number.

115232463894161 is a deficient number, since it is larger than the sum of its proper divisors (1).

115232463894161 is an equidigital number, since it uses as much as digits as its factorization.

115232463894161 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7464960, while the sum is 56.

The spelling of 115232463894161 in words is "one hundred fifteen trillion, two hundred thirty-two billion, four hundred sixty-three million, eight hundred ninety-four thousand, one hundred sixty-one".