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115240232103 = 3291324600369
BaseRepresentation
bin110101101010011011…
…0100110010010100111
3102000110021211100102120
41223110312212102213
53342002444411403
6124535102041023
711216521545033
oct1532466462247
9360407740376
10115240232103
114496711a047
121a401879173
13ab3705b169
14581313b1c3
152ee71a3e53
hex1ad4da64a7

115240232103 has 8 divisors (see below), whose sum is σ = 158952044400. Its totient is φ = 74177620608.

The previous prime is 115240231999. The next prime is 115240232137. The reversal of 115240232103 is 301232042511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 115240232103 - 29 = 115240231591 is a prime.

It is a super-2 number, since 2×1152402321032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115240232803) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 662300098 + ... + 662300271.

It is an arithmetic number, because the mean of its divisors is an integer number (19869005550).

Almost surely, 2115240232103 is an apocalyptic number.

115240232103 is a deficient number, since it is larger than the sum of its proper divisors (43711812297).

115240232103 is a wasteful number, since it uses less digits than its factorization.

115240232103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1324600401.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 115240232103 its reverse (301232042511), we get a palindrome (416472274614).

The spelling of 115240232103 in words is "one hundred fifteen billion, two hundred forty million, two hundred thirty-two thousand, one hundred three".

Divisors: 1 3 29 87 1324600369 3973801107 38413410701 115240232103