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115240232537 is a prime number
BaseRepresentation
bin110101101010011011…
…0100110011001011001
3102000110021211101000122
41223110312212121121
53342002444420122
6124535102043025
711216521546223
oct1532466463131
9360407741018
10115240232537
114496711a401
121a401879475
13ab3705b411
14581313b413
152ee71a4142
hex1ad4da6659

115240232537 has 2 divisors, whose sum is σ = 115240232538. Its totient is φ = 115240232536.

The previous prime is 115240232453. The next prime is 115240232563. The reversal of 115240232537 is 735232042511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114908118361 + 332114176 = 338981^2 + 18224^2 .

It is a cyclic number.

It is not a de Polignac number, because 115240232537 - 222 = 115236038233 is a prime.

It is a super-2 number, since 2×1152402325372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115240232497 and 115240232506.

It is not a weakly prime, because it can be changed into another prime (115240232137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57620116268 + 57620116269.

It is an arithmetic number, because the mean of its divisors is an integer number (57620116269).

Almost surely, 2115240232537 is an apocalyptic number.

It is an amenable number.

115240232537 is a deficient number, since it is larger than the sum of its proper divisors (1).

115240232537 is an equidigital number, since it uses as much as digits as its factorization.

115240232537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 115240232537 in words is "one hundred fifteen billion, two hundred forty million, two hundred thirty-two thousand, five hundred thirty-seven".