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1152425414489 is a prime number
BaseRepresentation
bin10000110001010001111…
…010000100111101011001
311002011121111201202112212
4100301101322010331121
5122340131401230424
62241230020044505
7146155114253366
oct20612172047531
94064544652485
101152425414489
11404817114928
12167420b33735
138489a1916ab
143dac5d9146d
151ee9d23c10e
hex10c51e84f59

1152425414489 has 2 divisors, whose sum is σ = 1152425414490. Its totient is φ = 1152425414488.

The previous prime is 1152425414431. The next prime is 1152425414521. The reversal of 1152425414489 is 9844145242511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1128619393225 + 23806021264 = 1062365^2 + 154292^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1152425414489 is a prime.

It is a super-3 number, since 3×11524254144893 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1152425417489) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576212707244 + 576212707245.

It is an arithmetic number, because the mean of its divisors is an integer number (576212707245).

Almost surely, 21152425414489 is an apocalyptic number.

It is an amenable number.

1152425414489 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152425414489 is an equidigital number, since it uses as much as digits as its factorization.

1152425414489 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1843200, while the sum is 50.

The spelling of 1152425414489 in words is "one trillion, one hundred fifty-two billion, four hundred twenty-five million, four hundred fourteen thousand, four hundred eighty-nine".