Base | Representation |
---|---|
bin | 1010011110110111100011… |
… | …0000011100101000111111 |
3 | 1111210211010120010211212020 |
4 | 2213231320300130220333 |
5 | 3002313031321040221 |
6 | 40302412322411223 |
7 | 2266453505652516 |
oct | 247557060345077 |
9 | 44724116124766 |
10 | 11525423221311 |
11 | 37439a4a3990a |
12 | 1361854b00b13 |
13 | 657ac568a33c |
14 | 2bbb9502d67d |
15 | 14ec0920dac6 |
hex | a7b78c1ca3f |
11525423221311 has 4 divisors (see below), whose sum is σ = 15367230961752. Its totient is φ = 7683615480872.
The previous prime is 11525423221307. The next prime is 11525423221321. The reversal of 11525423221311 is 11312232452511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11525423221311 - 22 = 11525423221307 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11525423221321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1920903870216 + ... + 1920903870221.
It is an arithmetic number, because the mean of its divisors is an integer number (3841807740438).
Almost surely, 211525423221311 is an apocalyptic number.
11525423221311 is a deficient number, since it is larger than the sum of its proper divisors (3841807740441).
11525423221311 is an equidigital number, since it uses as much as digits as its factorization.
11525423221311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3841807740440.
The product of its digits is 14400, while the sum is 33.
Adding to 11525423221311 its reverse (11312232452511), we get a palindrome (22837655673822).
The spelling of 11525423221311 in words is "eleven trillion, five hundred twenty-five billion, four hundred twenty-three million, two hundred twenty-one thousand, three hundred eleven".
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