Base | Representation |
---|---|
bin | 1010011110110111100011… |
… | …0000011100101000111011 |
3 | 1111210211010120010211212002 |
4 | 2213231320300130220323 |
5 | 3002313031321040212 |
6 | 40302412322411215 |
7 | 2266453505652512 |
oct | 247557060345073 |
9 | 44724116124762 |
10 | 11525423221307 |
11 | 37439a4a39906 |
12 | 1361854b00b0b |
13 | 657ac568a338 |
14 | 2bbb9502d679 |
15 | 14ec0920dac2 |
hex | a7b78c1ca3b |
11525423221307 has 2 divisors, whose sum is σ = 11525423221308. Its totient is φ = 11525423221306.
The previous prime is 11525423221271. The next prime is 11525423221321. The reversal of 11525423221307 is 70312232452511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11525423221307 - 220 = 11525422172731 is a prime.
It is a super-3 number, since 3×115254232213073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11525423220307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762711610653 + 5762711610654.
It is an arithmetic number, because the mean of its divisors is an integer number (5762711610654).
Almost surely, 211525423221307 is an apocalyptic number.
11525423221307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525423221307 is an equidigital number, since it uses as much as digits as its factorization.
11525423221307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 11525423221307 its reverse (70312232452511), we get a palindrome (81837655673818).
The spelling of 11525423221307 in words is "eleven trillion, five hundred twenty-five billion, four hundred twenty-three million, two hundred twenty-one thousand, three hundred seven".
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