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11525913473 is a prime number
BaseRepresentation
bin10101011101111111…
…10111101110000001
31002202021001001220012
422232333313232001
5142101113212343
65143412154305
7555423435164
oct125677675601
932667031805
1011525913473
114985094428
122298008995
131118b83659
147b4a8dadb
15476d25718
hex2aeff7b81

11525913473 has 2 divisors, whose sum is σ = 11525913474. Its totient is φ = 11525913472.

The previous prime is 11525913463. The next prime is 11525913493. The reversal of 11525913473 is 37431952511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10062697969 + 1463215504 = 100313^2 + 38252^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11525913473 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11525913473.

It is not a weakly prime, because it can be changed into another prime (11525913403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762956736 + 5762956737.

It is an arithmetic number, because the mean of its divisors is an integer number (5762956737).

Almost surely, 211525913473 is an apocalyptic number.

It is an amenable number.

11525913473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11525913473 is an equidigital number, since it uses as much as digits as its factorization.

11525913473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 113400, while the sum is 41.

The spelling of 11525913473 in words is "eleven billion, five hundred twenty-five million, nine hundred thirteen thousand, four hundred seventy-three".