Base | Representation |
---|---|
bin | 10101011101111111… |
… | …10111101110000001 |
3 | 1002202021001001220012 |
4 | 22232333313232001 |
5 | 142101113212343 |
6 | 5143412154305 |
7 | 555423435164 |
oct | 125677675601 |
9 | 32667031805 |
10 | 11525913473 |
11 | 4985094428 |
12 | 2298008995 |
13 | 1118b83659 |
14 | 7b4a8dadb |
15 | 476d25718 |
hex | 2aeff7b81 |
11525913473 has 2 divisors, whose sum is σ = 11525913474. Its totient is φ = 11525913472.
The previous prime is 11525913463. The next prime is 11525913493. The reversal of 11525913473 is 37431952511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10062697969 + 1463215504 = 100313^2 + 38252^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11525913473 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 11525913473.
It is not a weakly prime, because it can be changed into another prime (11525913403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762956736 + 5762956737.
It is an arithmetic number, because the mean of its divisors is an integer number (5762956737).
Almost surely, 211525913473 is an apocalyptic number.
It is an amenable number.
11525913473 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525913473 is an equidigital number, since it uses as much as digits as its factorization.
11525913473 is an evil number, because the sum of its binary digits is even.
The product of its digits is 113400, while the sum is 41.
The spelling of 11525913473 in words is "eleven billion, five hundred twenty-five million, nine hundred thirteen thousand, four hundred seventy-three".
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