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115300143235609 is a prime number
BaseRepresentation
bin11010001101110101101000…
…000101001000001000011001
3120010020120211020010001120221
4122031311220011020020121
5110103034143132014414
61045120053215320041
733200106014632033
oct3215655005101031
9503216736101527
10115300143235609
1133813574a95a92
1210b21b34820021
134c449aba65307
1420687b1872c53
15d4e34be88224
hex68dd68148219

115300143235609 has 2 divisors, whose sum is σ = 115300143235610. Its totient is φ = 115300143235608.

The previous prime is 115300143235531. The next prime is 115300143235619. The reversal of 115300143235609 is 906532341003511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63117622515600 + 52182520720009 = 7944660^2 + 7223747^2 .

It is a cyclic number.

It is not a de Polignac number, because 115300143235609 - 29 = 115300143235097 is a prime.

It is not a weakly prime, because it can be changed into another prime (115300143235619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57650071617804 + 57650071617805.

It is an arithmetic number, because the mean of its divisors is an integer number (57650071617805).

Almost surely, 2115300143235609 is an apocalyptic number.

It is an amenable number.

115300143235609 is a deficient number, since it is larger than the sum of its proper divisors (1).

115300143235609 is an equidigital number, since it uses as much as digits as its factorization.

115300143235609 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 291600, while the sum is 43.

The spelling of 115300143235609 in words is "one hundred fifteen trillion, three hundred billion, one hundred forty-three million, two hundred thirty-five thousand, six hundred nine".