11530114003 has 2 divisors, whose sum is σ = 11530114004. Its totient is φ = 11530114002.

The previous prime is 11530113979. The next prime is 11530114007. The reversal of 11530114003 is 30041103511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11530114003 - 2⁵ = 11530113971 is a prime.

It is a super-3 number, since 3×11530114003³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11530114007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765057001 + 5765057002.

It is an arithmetic number, because the mean of its divisors is an integer number (5765057002).

Almost surely, 2^11530114003 is an apocalyptic number.

11530114003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11530114003 is an equidigital number, since it uses as much as digits as its factorization.

11530114003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 11530114003 its reverse (30041103511), we get a palindrome (41571217514).

The spelling of 11530114003 in words is "eleven billion, five hundred thirty million, one hundred fourteen thousand, three".