115303324315441 has 2 divisors, whose sum is σ = 115303324315442. Its totient is φ = 115303324315440.

The previous prime is 115303324315433. The next prime is 115303324315471. The reversal of 115303324315441 is 144513423303511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81445589127841 + 33857735187600 = 9024721^2 + 5818740^2 .

It is an emirp because it is prime and its reverse (144513423303511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115303324315441 - 2³ = 115303324315433 is a prime.

It is a super-3 number, since 3×115303324315441³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115303324315394 and 115303324315403.

It is not a weakly prime, because it can be changed into another prime (115303324315471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57651662157720 + 57651662157721.

It is an arithmetic number, because the mean of its divisors is an integer number (57651662157721).

Almost surely, 2^{115303324315441} is an apocalyptic number.

It is an amenable number.

115303324315441 is a deficient number, since it is larger than the sum of its proper divisors (1).

115303324315441 is an equidigital number, since it uses as much as digits as its factorization.

115303324315441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 115303324315441 its reverse (144513423303511), we get a palindrome (259816747618952).

The spelling of 115303324315441 in words is "one hundred fifteen trillion, three hundred three billion, three hundred twenty-four million, three hundred fifteen thousand, four hundred forty-one".