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1153054202401 is a prime number
BaseRepresentation
bin10000110001110111011…
…000101101101000100001
311002020020022220111102001
4100301313120231220201
5122342423333434101
62241412241124001
7146206521002323
oct20616730555041
94066208814361
101153054202401
1140500a045562
12167577629601
138496a52964a
143db456ad613
151eed8544901
hex10c7762da21

1153054202401 has 2 divisors, whose sum is σ = 1153054202402. Its totient is φ = 1153054202400.

The previous prime is 1153054202383. The next prime is 1153054202437. The reversal of 1153054202401 is 1042024503511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 744734480400 + 408319722001 = 862980^2 + 638999^2 .

It is a cyclic number.

It is not a de Polignac number, because 1153054202401 - 219 = 1153053678113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1153054202401.

It is not a weakly prime, because it can be changed into another prime (1153054202101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576527101200 + 576527101201.

It is an arithmetic number, because the mean of its divisors is an integer number (576527101201).

Almost surely, 21153054202401 is an apocalyptic number.

It is an amenable number.

1153054202401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153054202401 is an equidigital number, since it uses as much as digits as its factorization.

1153054202401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 1153054202401 its reverse (1042024503511), we get a palindrome (2195078705912).

The spelling of 1153054202401 in words is "one trillion, one hundred fifty-three billion, fifty-four million, two hundred two thousand, four hundred one".