Base | Representation |
---|---|
bin | 10000110001111100001… |
… | …110001110111011000101 |
3 | 11002020102222120202222201 |
4 | 100301330032032323011 |
5 | 122343110121410003 |
6 | 2241424300154501 |
7 | 146211524450620 |
oct | 20617416167305 |
9 | 4066388522881 |
10 | 1153135341253 |
11 | 405050924365 |
12 | 16759a838a31 |
13 | 849812981bc |
14 | 3db52390db7 |
15 | 1eee0720b1d |
hex | 10c7c38eec5 |
1153135341253 has 8 divisors (see below), whose sum is σ = 1318002145280. Its totient is φ = 988301833200.
The previous prime is 1153135341251. The next prime is 1153135341283. The reversal of 1153135341253 is 3521435313511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1153135341253 - 21 = 1153135341251 is a prime.
It is a super-2 number, since 2×11531353412532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1153135341251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8249733 + ... + 8388346.
It is an arithmetic number, because the mean of its divisors is an integer number (164750268160).
Almost surely, 21153135341253 is an apocalyptic number.
It is an amenable number.
1153135341253 is a deficient number, since it is larger than the sum of its proper divisors (164866804027).
1153135341253 is an equidigital number, since it uses as much as digits as its factorization.
1153135341253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16647987.
The product of its digits is 81000, while the sum is 37.
The spelling of 1153135341253 in words is "one trillion, one hundred fifty-three billion, one hundred thirty-five million, three hundred forty-one thousand, two hundred fifty-three".
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