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115315250143481 is a prime number
BaseRepresentation
bin11010001110000011101100…
…100001011010000011111001
3120010022000211001102111022022
4122032003230201122003321
5110103311113014042411
61045131032233004225
733201152253344153
oct3216035441320371
9503260731374268
10115315250143481
1133819a17497513
1210b24a4bb53675
134c462487a315b
142069405d65ad3
15d4e933368edb
hex68e0ec85a0f9

115315250143481 has 2 divisors, whose sum is σ = 115315250143482. Its totient is φ = 115315250143480.

The previous prime is 115315250143381. The next prime is 115315250143493. The reversal of 115315250143481 is 184341052513511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114892673440000 + 422576703481 = 10718800^2 + 650059^2 .

It is an emirp because it is prime and its reverse (184341052513511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115315250143481 - 222 = 115315245949177 is a prime.

It is a super-2 number, since 2×1153152501434812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115315250143081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57657625071740 + 57657625071741.

It is an arithmetic number, because the mean of its divisors is an integer number (57657625071741).

Almost surely, 2115315250143481 is an apocalyptic number.

It is an amenable number.

115315250143481 is a deficient number, since it is larger than the sum of its proper divisors (1).

115315250143481 is an equidigital number, since it uses as much as digits as its factorization.

115315250143481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 44.

The spelling of 115315250143481 in words is "one hundred fifteen trillion, three hundred fifteen billion, two hundred fifty million, one hundred forty-three thousand, four hundred eighty-one".