Base | Representation |
---|---|
bin | 1010011111010000000011… |
… | …0010011010011000110101 |
3 | 1111211110002221021101202210 |
4 | 2213310000302122120311 |
5 | 3002420014100430140 |
6 | 40305421114324033 |
7 | 2300105502051351 |
oct | 247640062323065 |
9 | 44743087241683 |
10 | 11532000405045 |
11 | 374676a65434a |
12 | 1362b8b729619 |
13 | 6586031c3733 |
14 | 2bc21a766461 |
15 | 14ee91858d80 |
hex | a7d00c9a635 |
11532000405045 has 16 divisors (see below), whose sum is σ = 18451242830592. Its totient is φ = 6150386155200.
The previous prime is 11532000405019. The next prime is 11532000405061. The reversal of 11532000405045 is 54050400023511.
It is not a de Polignac number, because 11532000405045 - 210 = 11532000404021 is a prime.
It is a super-2 number, since 2×115320004050452 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11826564 + ... + 12764466.
It is an arithmetic number, because the mean of its divisors is an integer number (1153202676912).
Almost surely, 211532000405045 is an apocalyptic number.
11532000405045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11532000405045 is a deficient number, since it is larger than the sum of its proper divisors (6919242425547).
11532000405045 is an equidigital number, since it uses as much as digits as its factorization.
11532000405045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1757612.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 11532000405045 its reverse (54050400023511), we get a palindrome (65582400428556).
The spelling of 11532000405045 in words is "eleven trillion, five hundred thirty-two billion, four hundred five thousand, forty-five".
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