Base | Representation |
---|---|
bin | 1010011111010001101001… |
… | …1110010011100111100111 |
3 | 1111211111012222011021012210 |
4 | 2213310122132103213213 |
5 | 3002421404410421210 |
6 | 40305531551014503 |
7 | 2300122254003441 |
oct | 247643236234747 |
9 | 44744188137183 |
10 | 11532431342055 |
11 | 374697092a738 |
12 | 136308bb0a433 |
13 | 658671577650 |
14 | 2bc25baa1491 |
15 | 14eeb95cde20 |
hex | a7d1a7939e7 |
11532431342055 has 32 divisors (see below), whose sum is σ = 20143475464896. Its totient is φ = 5599730617344.
The previous prime is 11532431342051. The next prime is 11532431342071. The reversal of 11532431342055 is 55024313423511.
It is not a de Polignac number, because 11532431342055 - 22 = 11532431342051 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11532431342051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 405058872 + ... + 405087341.
It is an arithmetic number, because the mean of its divisors is an integer number (629483608278).
Almost surely, 211532431342055 is an apocalyptic number.
11532431342055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11532431342055 is a deficient number, since it is larger than the sum of its proper divisors (8611044122841).
11532431342055 is a wasteful number, since it uses less digits than its factorization.
11532431342055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 810146307.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 11532431342055 its reverse (55024313423511), we get a palindrome (66556744765566).
The spelling of 11532431342055 in words is "eleven trillion, five hundred thirty-two billion, four hundred thirty-one million, three hundred forty-two thousand, fifty-five".
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