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115325137 is a prime number
BaseRepresentation
bin1101101111110…
…11100011010001
322001000010100101
412313323203101
5214010401022
615235452401
72600150614
oct667734321
9261003311
10115325137
115a109534
1232757101
131ab7b135
141146017b
15a1d0627
hex6dfb8d1

115325137 has 2 divisors, whose sum is σ = 115325138. Its totient is φ = 115325136.

The previous prime is 115325129. The next prime is 115325149. The reversal of 115325137 is 731523511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59613841 + 55711296 = 7721^2 + 7464^2 .

It is a cyclic number.

It is not a de Polignac number, because 115325137 - 23 = 115325129 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115325437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57662568 + 57662569.

It is an arithmetic number, because the mean of its divisors is an integer number (57662569).

Almost surely, 2115325137 is an apocalyptic number.

It is an amenable number.

115325137 is a deficient number, since it is larger than the sum of its proper divisors (1).

115325137 is an equidigital number, since it uses as much as digits as its factorization.

115325137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3150, while the sum is 28.

The square root of 115325137 is about 10738.9541855806. The cubic root of 115325137 is about 486.7522784168.

Adding to 115325137 its reverse (731523511), we get a palindrome (846848648).

The spelling of 115325137 in words is "one hundred fifteen million, three hundred twenty-five thousand, one hundred thirty-seven".