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115325213543 = 1131020577111
BaseRepresentation
bin110101101100111101…
…0110001101101100111
3102000200012201212001022
41223121322301231213
53342141223313133
6124551335321355
711221603066241
oct1533172615547
9360605655038
10115325213543
1144a00092941
121a42622025b
13ab4b843a37
14582053d091
152eee88d998
hex1ad9eb1b67

115325213543 has 4 divisors (see below), whose sum is σ = 116345790768. Its totient is φ = 114304636320.

The previous prime is 115325213527. The next prime is 115325213551. The reversal of 115325213543 is 345312523511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115325213543 - 24 = 115325213527 is a prime.

It is a super-3 number, since 3×1153252135433 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115325213503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510288443 + ... + 510288668.

It is an arithmetic number, because the mean of its divisors is an integer number (29086447692).

Almost surely, 2115325213543 is an apocalyptic number.

115325213543 is a deficient number, since it is larger than the sum of its proper divisors (1020577225).

115325213543 is a wasteful number, since it uses less digits than its factorization.

115325213543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1020577224.

The product of its digits is 54000, while the sum is 35.

The spelling of 115325213543 in words is "one hundred fifteen billion, three hundred twenty-five million, two hundred thirteen thousand, five hundred forty-three".

Divisors: 1 113 1020577111 115325213543