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115325220234313 is a prime number
BaseRepresentation
bin11010001110001100111110…
…110010010010010001001001
3120010022222112212220120202201
4122032030332302102101021
5110103442022334444223
61045135401430400201
733201654315616315
oct3216147662222111
9503288485816681
10115325220234313
1133823173333301
1210b26972b00061
134c4717721aa9b
142069ab0140b45
15d4ed187b9ead
hex68e33ec92449

115325220234313 has 2 divisors, whose sum is σ = 115325220234314. Its totient is φ = 115325220234312.

The previous prime is 115325220234283. The next prime is 115325220234337. The reversal of 115325220234313 is 313432022523511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67734924595129 + 47590295639184 = 8230123^2 + 6898572^2 .

It is an emirp because it is prime and its reverse (313432022523511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115325220234313 - 225 = 115325186679881 is a prime.

It is not a weakly prime, because it can be changed into another prime (115325220234113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57662610117156 + 57662610117157.

It is an arithmetic number, because the mean of its divisors is an integer number (57662610117157).

Almost surely, 2115325220234313 is an apocalyptic number.

It is an amenable number.

115325220234313 is a deficient number, since it is larger than the sum of its proper divisors (1).

115325220234313 is an equidigital number, since it uses as much as digits as its factorization.

115325220234313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 115325220234313 its reverse (313432022523511), we get a palindrome (428757242757824).

The spelling of 115325220234313 in words is "one hundred fifteen trillion, three hundred twenty-five billion, two hundred twenty million, two hundred thirty-four thousand, three hundred thirteen".