115333225133 has 4 divisors (see below), whose sum is σ = 131809400160. Its totient is φ = 98857050108.

The previous prime is 115333225087. The next prime is 115333225151. The reversal of 115333225133 is 331522333511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115333225133 - 2¹⁰ = 115333224109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115333225133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115333225153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8238087503 + ... + 8238087516.

It is an arithmetic number, because the mean of its divisors is an integer number (32952350040).

Almost surely, 2^115333225133 is an apocalyptic number.

It is an amenable number.

115333225133 is a deficient number, since it is larger than the sum of its proper divisors (16476175027).

115333225133 is an equidigital number, since it uses as much as digits as its factorization.

115333225133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16476175026.

The product of its digits is 24300, while the sum is 32.

Adding to 115333225133 its reverse (331522333511), we get a palindrome (446855558644).

The spelling of 115333225133 in words is "one hundred fifteen billion, three hundred thirty-three million, two hundred twenty-five thousand, one hundred thirty-three".