Base | Representation |
---|---|
bin | 11010001110011011111110… |
… | …000101001111110111101011 |
3 | 120010101112002112012210201211 |
4 | 122032123332011033313223 |
5 | 110104223003011232441 |
6 | 1045151022435453551 |
7 | 33203064204240202 |
oct | 3216337605176753 |
9 | 503345075183654 |
10 | 115341314555371 |
11 | 33829a82140993 |
12 | 10b29b04a572b7 |
13 | 4c488406a9998 |
14 | 206a799826239 |
15 | d5045b6e2a81 |
hex | 68e6fe14fdeb |
115341314555371 has 32 divisors (see below), whose sum is σ = 121405395234816. Its totient is φ = 109366557300000.
The previous prime is 115341314555267. The next prime is 115341314555503. The reversal of 115341314555371 is 173555413143511.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115341314555371 is a prime.
It is a super-2 number, since 2×1153413145553712 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (115341314556371) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13096545450 + ... + 13096554256.
It is an arithmetic number, because the mean of its divisors is an integer number (3793918601088).
Almost surely, 2115341314555371 is an apocalyptic number.
115341314555371 is a deficient number, since it is larger than the sum of its proper divisors (6064080679445).
115341314555371 is a wasteful number, since it uses less digits than its factorization.
115341314555371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13143.
The product of its digits is 1890000, while the sum is 49.
Adding to 115341314555371 its reverse (173555413143511), we get a palindrome (288896727698882).
The spelling of 115341314555371 in words is "one hundred fifteen trillion, three hundred forty-one billion, three hundred fourteen million, five hundred fifty-five thousand, three hundred seventy-one".
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