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1153431131 is a prime number
BaseRepresentation
bin100010010111111…
…1111011001011011
32222101101101001112
41010233333121123
54330234244011
6310242010535
740404000656
oct10457773133
92871341045
101153431131
11542099976
12282346a4b
13154c6aa38
14ad28a89d
156b3dc58b
hex44bff65b

1153431131 has 2 divisors, whose sum is σ = 1153431132. Its totient is φ = 1153431130.

The previous prime is 1153431107. The next prime is 1153431143. The reversal of 1153431131 is 1311343511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1153431131 - 218 = 1153168987 is a prime.

It is a super-2 number, since 2×11534311312 = 2660806747919878322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1153431097 and 1153431106.

It is not a weakly prime, because it can be changed into another prime (1153431101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576715565 + 576715566.

It is an arithmetic number, because the mean of its divisors is an integer number (576715566).

Almost surely, 21153431131 is an apocalyptic number.

1153431131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153431131 is an equidigital number, since it uses as much as digits as its factorization.

1153431131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 540, while the sum is 23.

The square root of 1153431131 is about 33962.2015040250. The cubic root of 1153431131 is about 1048.7304780757.

Adding to 1153431131 its reverse (1311343511), we get a palindrome (2464774642).

The spelling of 1153431131 in words is "one billion, one hundred fifty-three million, four hundred thirty-one thousand, one hundred thirty-one".