Base | Representation |
---|---|
bin | 10101011110111111… |
… | …11101001010110001 |
3 | 1002202211212101112001 |
4 | 22233133331022301 |
5 | 142110241340101 |
6 | 5144312334001 |
7 | 555555065635 |
oct | 125737751261 |
9 | 32684771461 |
10 | 11534324401 |
11 | 4989909706 |
12 | 229a9a4301 |
13 | 111a839b32 |
14 | 7b5c3cdc5 |
15 | 477937901 |
hex | 2af7fd2b1 |
11534324401 has 2 divisors, whose sum is σ = 11534324402. Its totient is φ = 11534324400.
The previous prime is 11534324387. The next prime is 11534324423. The reversal of 11534324401 is 10442343511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7700238001 + 3834086400 = 87751^2 + 61920^2 .
It is a cyclic number.
It is not a de Polignac number, because 11534324401 - 211 = 11534322353 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11534324401.
It is not a weakly prime, because it can be changed into another prime (11534324201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767162200 + 5767162201.
It is an arithmetic number, because the mean of its divisors is an integer number (5767162201).
Almost surely, 211534324401 is an apocalyptic number.
It is an amenable number.
11534324401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11534324401 is an equidigital number, since it uses as much as digits as its factorization.
11534324401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 11534324401 its reverse (10442343511), we get a palindrome (21976667912).
The spelling of 11534324401 in words is "eleven billion, five hundred thirty-four million, three hundred twenty-four thousand, four hundred one".
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