Base | Representation |
---|---|
bin | 10000110010001110011… |
… | …001010000011111011111 |
3 | 11002021020020021021120210 |
4 | 100302032121100133133 |
5 | 122344221144034101 |
6 | 2241514430543503 |
7 | 146222216053401 |
oct | 20621631203737 |
9 | 4067206237523 |
10 | 1153440221151 |
11 | 405197a31119 |
12 | 167664967b93 |
13 | 849cc4b41ca |
14 | 3db80a74b71 |
15 | 2000c3957d6 |
hex | 10c8e6507df |
1153440221151 has 4 divisors (see below), whose sum is σ = 1537920294872. Its totient is φ = 768960147432.
The previous prime is 1153440221137. The next prime is 1153440221177. The reversal of 1153440221151 is 1511220443511.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1153440221151 - 213 = 1153440212959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1153440225151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192240036856 + ... + 192240036861.
It is an arithmetic number, because the mean of its divisors is an integer number (384480073718).
Almost surely, 21153440221151 is an apocalyptic number.
1153440221151 is a deficient number, since it is larger than the sum of its proper divisors (384480073721).
1153440221151 is an equidigital number, since it uses as much as digits as its factorization.
1153440221151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 384480073720.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 1153440221151 its reverse (1511220443511), we get a palindrome (2664660664662).
The spelling of 1153440221151 in words is "one trillion, one hundred fifty-three billion, four hundred forty million, two hundred twenty-one thousand, one hundred fifty-one".
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