Base | Representation |
---|---|
bin | 110101101101101100… |
… | …1101010100110010001 |
3 | 102000201221112121111111 |
4 | 1223123121222212101 |
5 | 3342214110304311 |
6 | 124554024413321 |
7 | 11222324366614 |
oct | 1533331524621 |
9 | 360657477444 |
10 | 115350088081 |
11 | 44a13132508 |
12 | 1a432617241 |
13 | ab53a42ab7 |
14 | 582397617b |
15 | 3001b53d21 |
hex | 1adb66a991 |
115350088081 has 2 divisors, whose sum is σ = 115350088082. Its totient is φ = 115350088080.
The previous prime is 115350088057. The next prime is 115350088097. The reversal of 115350088081 is 180880053511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64292166481 + 51057921600 = 253559^2 + 225960^2 .
It is a cyclic number.
It is not a de Polignac number, because 115350088081 - 231 = 113202604433 is a prime.
It is a super-2 number, since 2×1153500880812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115350089081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57675044040 + 57675044041.
It is an arithmetic number, because the mean of its divisors is an integer number (57675044041).
Almost surely, 2115350088081 is an apocalyptic number.
It is an amenable number.
115350088081 is a deficient number, since it is larger than the sum of its proper divisors (1).
115350088081 is an equidigital number, since it uses as much as digits as its factorization.
115350088081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 40.
The spelling of 115350088081 in words is "one hundred fifteen billion, three hundred fifty million, eighty-eight thousand, eighty-one".
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