115350336013151 has 4 divisors (see below), whose sum is σ = 116646407204400. Its totient is φ = 114054264821904.

The previous prime is 115350336013147. The next prime is 115350336013247. The reversal of 115350336013151 is 151310633053511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115350336013151 - 2² = 115350336013147 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115350336093151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648035595491 + ... + 648035595668.

It is an arithmetic number, because the mean of its divisors is an integer number (29161601801100).

Almost surely, 2^{115350336013151} is an apocalyptic number.

115350336013151 is a deficient number, since it is larger than the sum of its proper divisors (1296071191249).

115350336013151 is an equidigital number, since it uses as much as digits as its factorization.

115350336013151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1296071191248.

The product of its (nonzero) digits is 60750, while the sum is 38.

Adding to 115350336013151 its reverse (151310633053511), we get a palindrome (266660969066662).

The spelling of 115350336013151 in words is "one hundred fifteen trillion, three hundred fifty billion, three hundred thirty-six million, thirteen thousand, one hundred fifty-one".