1153532410433 has 32 divisors (see below), whose sum is σ = 1288325969280. Its totient is φ = 1026069258240.

The previous prime is 1153532410409. The next prime is 1153532410447. The reversal of 1153532410433 is 3340142353511.

It is not a de Polignac number, because 1153532410433 - 2⁴⁰ = 54020782657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1153532410393 and 1153532410402.

It is not an unprimeable number, because it can be changed into a prime (1153532410733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46858298 + ... + 46882908.

It is an arithmetic number, because the mean of its divisors is an integer number (40260186540).

Almost surely, 2^{1153532410433} is an apocalyptic number.

1153532410433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1153532410433 is a deficient number, since it is larger than the sum of its proper divisors (134793558847).

1153532410433 is a wasteful number, since it uses less digits than its factorization.

1153532410433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25889.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1153532410433 its reverse (3340142353511), we get a palindrome (4493674763944).

The spelling of 1153532410433 in words is "one trillion, one hundred fifty-three billion, five hundred thirty-two million, four hundred ten thousand, four hundred thirty-three".