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11535401123 is a prime number
BaseRepresentation
bin10101011111001000…
…00100000010100011
31002202220220002111122
422233210010002203
5142111030313443
65144351402455
7555600202031
oct125744040243
932686802448
1011535401123
11498a484664
12229b22342b
13111ab25c4c
147b603d551
15477a9b968
hex2af9040a3

11535401123 has 2 divisors, whose sum is σ = 11535401124. Its totient is φ = 11535401122.

The previous prime is 11535401113. The next prime is 11535401159. The reversal of 11535401123 is 32110453511.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11535401123 is a prime.

It is a super-2 number, since 2×115354011232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11535401092 and 11535401101.

It is not a weakly prime, because it can be changed into another prime (11535401113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767700561 + 5767700562.

It is an arithmetic number, because the mean of its divisors is an integer number (5767700562).

Almost surely, 211535401123 is an apocalyptic number.

11535401123 is a deficient number, since it is larger than the sum of its proper divisors (1).

11535401123 is an equidigital number, since it uses as much as digits as its factorization.

11535401123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 11535401123 its reverse (32110453511), we get a palindrome (43645854634).

The spelling of 11535401123 in words is "eleven billion, five hundred thirty-five million, four hundred one thousand, one hundred twenty-three".