Base | Representation |
---|---|
bin | 10101011111001000… |
… | …01101111000101101 |
3 | 1002202220222010211100 |
4 | 22233210031320231 |
5 | 142111033111303 |
6 | 5144352313313 |
7 | 555600430434 |
oct | 125744157055 |
9 | 32686863740 |
10 | 11535441453 |
11 | 498a501998 |
12 | 229b242839 |
13 | 111ab3b403 |
14 | 7b605011b |
15 | 477aa88a3 |
hex | 2af90de2d |
11535441453 has 24 divisors (see below), whose sum is σ = 16771453920. Its totient is φ = 7640002080.
The previous prime is 11535441347. The next prime is 11535441457. The reversal of 11535441453 is 35414453511.
11535441453 is a `hidden beast` number, since 1 + 1 + 53 + 544 + 14 + 53 = 666.
It is not a de Polignac number, because 11535441453 - 29 = 11535440941 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11535441457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2064123 + ... + 2069703.
It is an arithmetic number, because the mean of its divisors is an integer number (698810580).
Almost surely, 211535441453 is an apocalyptic number.
It is an amenable number.
11535441453 is a deficient number, since it is larger than the sum of its proper divisors (5236012467).
11535441453 is a wasteful number, since it uses less digits than its factorization.
11535441453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7049 (or 7046 counting only the distinct ones).
The product of its digits is 72000, while the sum is 36.
Adding to 11535441453 its reverse (35414453511), we get a palindrome (46949894964).
The spelling of 11535441453 in words is "eleven billion, five hundred thirty-five million, four hundred forty-one thousand, four hundred fifty-three".
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