1153874801353 has 2 divisors, whose sum is σ = 1153874801354. Its totient is φ = 1153874801352.

The previous prime is 1153874801327. The next prime is 1153874801381. The reversal of 1153874801353 is 3531084783511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1125016606224 + 28858195129 = 1060668^2 + 169877^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1153874801353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1153874801297 and 1153874801306.

It is not a weakly prime, because it can be changed into another prime (1153874801393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576937400676 + 576937400677.

It is an arithmetic number, because the mean of its divisors is an integer number (576937400677).

Almost surely, 2^{1153874801353} is an apocalyptic number.

It is an amenable number.

1153874801353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153874801353 is an equidigital number, since it uses as much as digits as its factorization.

1153874801353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1209600, while the sum is 49.

The spelling of 1153874801353 in words is "one trillion, one hundred fifty-three billion, eight hundred seventy-four million, eight hundred one thousand, three hundred fifty-three".