11540062065041 has 2 divisors, whose sum is σ = 11540062065042. Its totient is φ = 11540062065040.

The previous prime is 11540062065029. The next prime is 11540062065047. The reversal of 11540062065041 is 14056026004511.

11540062065041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8333469900625 + 3206592164416 = 2886775^2 + 1790696^2 .

It is an emirp because it is prime and its reverse (14056026004511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11540062065041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11540062064992 and 11540062065010.

It is not a weakly prime, because it can be changed into another prime (11540062065047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770031032520 + 5770031032521.

It is an arithmetic number, because the mean of its divisors is an integer number (5770031032521).

Almost surely, 2^{11540062065041} is an apocalyptic number.

It is an amenable number.

11540062065041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540062065041 is an equidigital number, since it uses as much as digits as its factorization.

11540062065041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 11540062065041 its reverse (14056026004511), we get a palindrome (25596088069552).

The spelling of 11540062065041 in words is "eleven trillion, five hundred forty billion, sixty-two million, sixty-five thousand, forty-one".