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11540233 is a prime number
BaseRepresentation
bin101100000001…
…011100001001
3210201022020001
4230001130021
510423241413
61051203001
7200042665
oct54013411
923638201
1011540233
116572391
123a46461
132510953
1417658a5
15102e4dd
hexb01709

11540233 has 2 divisors, whose sum is σ = 11540234. Its totient is φ = 11540232.

The previous prime is 11540203. The next prime is 11540251. The reversal of 11540233 is 33204511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7033104 + 4507129 = 2652^2 + 2123^2 .

It is an emirp because it is prime and its reverse (33204511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11540233 - 217 = 11409161 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11540233.

It is not a weakly prime, because it can be changed into another prime (11540203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770116 + 5770117.

It is an arithmetic number, because the mean of its divisors is an integer number (5770117).

Almost surely, 211540233 is an apocalyptic number.

It is an amenable number.

11540233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540233 is an equidigital number, since it uses as much as digits as its factorization.

11540233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 11540233 is about 3397.0918445046. The cubic root of 11540233 is about 225.9807916951.

Adding to 11540233 its reverse (33204511), we get a palindrome (44744744).

The spelling of 11540233 in words is "eleven million, five hundred forty thousand, two hundred thirty-three".