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115402620331 is a prime number
BaseRepresentation
bin110101101111010001…
…0000011110110101011
3102000212121101112012101
41223132202003312223
53342321032322311
6125003142354231
711223533042065
oct1533642036653
9360777345171
10115402620331
1144a3a852799
121a44812b977
13ab618a697b
14582a92c735
15300657dec1
hex1ade883dab

115402620331 has 2 divisors, whose sum is σ = 115402620332. Its totient is φ = 115402620330.

The previous prime is 115402620317. The next prime is 115402620373. The reversal of 115402620331 is 133026204511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115402620331 - 211 = 115402618283 is a prime.

It is a super-2 number, since 2×1154026203312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115402620331.

It is not a weakly prime, because it can be changed into another prime (115402680331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701310165 + 57701310166.

It is an arithmetic number, because the mean of its divisors is an integer number (57701310166).

Almost surely, 2115402620331 is an apocalyptic number.

115402620331 is a deficient number, since it is larger than the sum of its proper divisors (1).

115402620331 is an equidigital number, since it uses as much as digits as its factorization.

115402620331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 115402620331 its reverse (133026204511), we get a palindrome (248428824842).

The spelling of 115402620331 in words is "one hundred fifteen billion, four hundred two million, six hundred twenty thousand, three hundred thirty-one".