Base | Representation |
---|---|
bin | 110101101111010001… |
… | …0000011110110101011 |
3 | 102000212121101112012101 |
4 | 1223132202003312223 |
5 | 3342321032322311 |
6 | 125003142354231 |
7 | 11223533042065 |
oct | 1533642036653 |
9 | 360777345171 |
10 | 115402620331 |
11 | 44a3a852799 |
12 | 1a44812b977 |
13 | ab618a697b |
14 | 582a92c735 |
15 | 300657dec1 |
hex | 1ade883dab |
115402620331 has 2 divisors, whose sum is σ = 115402620332. Its totient is φ = 115402620330.
The previous prime is 115402620317. The next prime is 115402620373. The reversal of 115402620331 is 133026204511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115402620331 - 211 = 115402618283 is a prime.
It is a super-2 number, since 2×1154026203312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 115402620331.
It is not a weakly prime, because it can be changed into another prime (115402680331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701310165 + 57701310166.
It is an arithmetic number, because the mean of its divisors is an integer number (57701310166).
Almost surely, 2115402620331 is an apocalyptic number.
115402620331 is a deficient number, since it is larger than the sum of its proper divisors (1).
115402620331 is an equidigital number, since it uses as much as digits as its factorization.
115402620331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 115402620331 its reverse (133026204511), we get a palindrome (248428824842).
The spelling of 115402620331 in words is "one hundred fifteen billion, four hundred two million, six hundred twenty thousand, three hundred thirty-one".
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