Base | Representation |
---|---|
bin | 1010011111101110111101… |
… | …1110001000100100001011 |
3 | 1111212020112100001220112121 |
4 | 2213323233132020210023 |
5 | 3003034013222423313 |
6 | 40313312431352111 |
7 | 2300521246615411 |
oct | 247735736104413 |
9 | 44766470056477 |
10 | 11540299811083 |
11 | 374a23942a9aa |
12 | 1364707082637 |
13 | 659326787194 |
14 | 2bc7a6acb2b1 |
15 | 1502ca29728d |
hex | a7eef78890b |
11540299811083 has 2 divisors, whose sum is σ = 11540299811084. Its totient is φ = 11540299811082.
The previous prime is 11540299811021. The next prime is 11540299811087. The reversal of 11540299811083 is 38011899204511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11540299811083 - 237 = 11402860857611 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11540299811083.
It is not a weakly prime, because it can be changed into another prime (11540299811087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770149905541 + 5770149905542.
It is an arithmetic number, because the mean of its divisors is an integer number (5770149905542).
Almost surely, 211540299811083 is an apocalyptic number.
11540299811083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11540299811083 is an equidigital number, since it uses as much as digits as its factorization.
11540299811083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 52.
The spelling of 11540299811083 in words is "eleven trillion, five hundred forty billion, two hundred ninety-nine million, eight hundred eleven thousand, eighty-three".
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