1154031122323 has 2 divisors, whose sum is σ = 1154031122324. Its totient is φ = 1154031122322.

The previous prime is 1154031122297. The next prime is 1154031122327. The reversal of 1154031122323 is 3232211304511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1154031122323 - 2⁵ = 1154031122291 is a prime.

It is a super-3 number, since 3×1154031122323³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1154031122291 and 1154031122300.

It is not a weakly prime, because it can be changed into another prime (1154031122327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577015561161 + 577015561162.

It is an arithmetic number, because the mean of its divisors is an integer number (577015561162).

Almost surely, 2^{1154031122323} is an apocalyptic number.

1154031122323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1154031122323 is an equidigital number, since it uses as much as digits as its factorization.

1154031122323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1154031122323 its reverse (3232211304511), we get a palindrome (4386242426834).

The spelling of 1154031122323 in words is "one trillion, one hundred fifty-four billion, thirty-one million, one hundred twenty-two thousand, three hundred twenty-three".