Base | Representation |
---|---|
bin | 110101101111010100… |
… | …1010011101001110011 |
3 | 102000212201222001010101 |
4 | 1223132221103221303 |
5 | 3342322024120201 |
6 | 125003251213231 |
7 | 11223555143452 |
oct | 1533651235163 |
9 | 360781861111 |
10 | 115404520051 |
11 | 44a40930007 |
12 | 1a4488a7217 |
13 | ab620c0572 |
14 | 582aca4b99 |
15 | 3006806d01 |
hex | 1adea53a73 |
115404520051 has 2 divisors, whose sum is σ = 115404520052. Its totient is φ = 115404520050.
The previous prime is 115404520013. The next prime is 115404520057. The reversal of 115404520051 is 150025404511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115404520051 is a prime.
It is a super-2 number, since 2×1154045200512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115404520057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57702260025 + 57702260026.
It is an arithmetic number, because the mean of its divisors is an integer number (57702260026).
Almost surely, 2115404520051 is an apocalyptic number.
115404520051 is a deficient number, since it is larger than the sum of its proper divisors (1).
115404520051 is an equidigital number, since it uses as much as digits as its factorization.
115404520051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
Adding to 115404520051 its reverse (150025404511), we get a palindrome (265429924562).
The spelling of 115404520051 in words is "one hundred fifteen billion, four hundred four million, five hundred twenty thousand, fifty-one".
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