Base | Representation |
---|---|
bin | 10101011111110011… |
… | …10100011111111001 |
3 | 1002210022121212020202 |
4 | 22233321310133321 |
5 | 142114010322013 |
6 | 5145113531545 |
7 | 555666525242 |
oct | 125771643771 |
9 | 32708555222 |
10 | 11541104633 |
11 | 499271a803 |
12 | 22a1113bb5 |
13 | 111c071cc6 |
14 | 7b6ac5cc9 |
15 | 478326858 |
hex | 2afe747f9 |
11541104633 has 2 divisors, whose sum is σ = 11541104634. Its totient is φ = 11541104632.
The previous prime is 11541104609. The next prime is 11541104681. The reversal of 11541104633 is 33640114511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11501061049 + 40043584 = 107243^2 + 6328^2 .
It is a cyclic number.
It is not a de Polignac number, because 11541104633 - 214 = 11541088249 is a prime.
It is a super-2 number, since 2×115411046332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11541104596 and 11541104605.
It is not a weakly prime, because it can be changed into another prime (1541104633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770552316 + 5770552317.
It is an arithmetic number, because the mean of its divisors is an integer number (5770552317).
Almost surely, 211541104633 is an apocalyptic number.
It is an amenable number.
11541104633 is a deficient number, since it is larger than the sum of its proper divisors (1).
11541104633 is an equidigital number, since it uses as much as digits as its factorization.
11541104633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 11541104633 in words is "eleven billion, five hundred forty-one million, one hundred four thousand, six hundred thirty-three".
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