11543325253 has 4 divisors (see below), whose sum is σ = 11546662048. Its totient is φ = 11539988460.

The previous prime is 11543325229. The next prime is 11543325319. The reversal of 11543325253 is 35252334511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11543325253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11543325203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1663203 + ... + 1670128.

It is an arithmetic number, because the mean of its divisors is an integer number (2886665512).

Almost surely, 2^11543325253 is an apocalyptic number.

It is an amenable number.

11543325253 is a deficient number, since it is larger than the sum of its proper divisors (3336795).

11543325253 is an equidigital number, since it uses as much as digits as its factorization.

11543325253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3336794.

The product of its digits is 54000, while the sum is 34.

Adding to 11543325253 its reverse (35252334511), we get a palindrome (46795659764).

The spelling of 11543325253 in words is "eleven billion, five hundred forty-three million, three hundred twenty-five thousand, two hundred fifty-three".