Base | Representation |
---|---|
bin | 10101100000000111… |
… | …00111000101001001 |
3 | 1002210111110020210120 |
4 | 22300003213011021 |
5 | 142120134433423 |
6 | 5145244533453 |
7 | 556030404552 |
oct | 126003470511 |
9 | 32714406716 |
10 | 11543671113 |
11 | 4994112a67 |
12 | 22a1b51289 |
13 | 111c760230 |
14 | 7b7193329 |
15 | 478681ee3 |
hex | 2b00e7149 |
11543671113 has 32 divisors (see below), whose sum is σ = 16819600896. Its totient is φ = 6999395328.
The previous prime is 11543671099. The next prime is 11543671151. The reversal of 11543671113 is 31117634511.
It is not a de Polignac number, because 11543671113 - 28 = 11543670857 is a prime.
It is a super-2 number, since 2×115436711132 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11543671813) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4716256 + ... + 4718702.
It is an arithmetic number, because the mean of its divisors is an integer number (525612528).
Almost surely, 211543671113 is an apocalyptic number.
11543671113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11543671113 is a deficient number, since it is larger than the sum of its proper divisors (5275929783).
11543671113 is a wasteful number, since it uses less digits than its factorization.
11543671113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4193.
The product of its digits is 7560, while the sum is 33.
The spelling of 11543671113 in words is "eleven billion, five hundred forty-three million, six hundred seventy-one thousand, one hundred thirteen".
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