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142120134433423 is a prime number
BaseRepresentation
bin100000010100000111101100…
…001000001101101010001111
3200122012112220112012221001101
4200110013230020031222033
5122111444013403332143
61222133031033523531
741635561263443536
oct4024075410155217
9618175815187041
10142120134433423
11413138a0906a53
1213b33a015735a7
13613bb42c6a823
142714918cb931d
151166d0e176b4d
hex8141ec20da8f

142120134433423 has 2 divisors, whose sum is σ = 142120134433424. Its totient is φ = 142120134433422.

The previous prime is 142120134433411. The next prime is 142120134433489. The reversal of 142120134433423 is 324334431021241.

It is a weak prime.

It is an emirp because it is prime and its reverse (324334431021241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142120134433423 - 25 = 142120134433391 is a prime.

It is a super-2 number, since 2×1421201344334232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142120134433523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71060067216711 + 71060067216712.

It is an arithmetic number, because the mean of its divisors is an integer number (71060067216712).

Almost surely, 2142120134433423 is an apocalyptic number.

142120134433423 is a deficient number, since it is larger than the sum of its proper divisors (1).

142120134433423 is an equidigital number, since it uses as much as digits as its factorization.

142120134433423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 142120134433423 its reverse (324334431021241), we get a palindrome (466454565454664).

The spelling of 142120134433423 in words is "one hundred forty-two trillion, one hundred twenty billion, one hundred thirty-four million, four hundred thirty-three thousand, four hundred twenty-three".