Base | Representation |
---|---|
bin | 110101110000011100… |
… | …0110000111110011011 |
3 | 102000222100201122210222 |
4 | 1223200320300332123 |
5 | 3342411141023442 |
6 | 125011113230255 |
7 | 11224522613123 |
oct | 1534070607633 |
9 | 360870648728 |
10 | 115442126747 |
11 | 44a60086522 |
12 | 1a45940238b |
13 | ab69b2994c |
14 | 5831c93c83 |
15 | 3009c848d2 |
hex | 1ae0e30f9b |
115442126747 has 2 divisors, whose sum is σ = 115442126748. Its totient is φ = 115442126746.
The previous prime is 115442126743. The next prime is 115442126753. The reversal of 115442126747 is 747621244511.
It is a weak prime.
It is an emirp because it is prime and its reverse (747621244511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115442126747 - 22 = 115442126743 is a prime.
It is a super-4 number, since 4×1154421267474 (a number of 45 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115442126698 and 115442126707.
It is not a weakly prime, because it can be changed into another prime (115442126743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57721063373 + 57721063374.
It is an arithmetic number, because the mean of its divisors is an integer number (57721063374).
Almost surely, 2115442126747 is an apocalyptic number.
115442126747 is a deficient number, since it is larger than the sum of its proper divisors (1).
115442126747 is an equidigital number, since it uses as much as digits as its factorization.
115442126747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 376320, while the sum is 44.
The spelling of 115442126747 in words is "one hundred fifteen billion, four hundred forty-two million, one hundred twenty-six thousand, seven hundred forty-seven".
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