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11544296957 = 91912561803
BaseRepresentation
bin10101100000001011…
…11111110111111101
31002210112122001021222
422300011333313331
5142120320000312
65145310203125
7556035622304
oct126005776775
932715561258
1011544296957
114994500196
1222a21b34a5
13111c91c05b
147b72b743b
15478757672
hex2b017fdfd

11544296957 has 4 divisors (see below), whose sum is σ = 11556859680. Its totient is φ = 11531734236.

The previous prime is 11544296893. The next prime is 11544296969. The reversal of 11544296957 is 75969244511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75969244511 = 611245397451.

It is a cyclic number.

It is not a de Polignac number, because 11544296957 - 26 = 11544296893 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11544296899 and 11544296908.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11544296977) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6279983 + ... + 6281820.

It is an arithmetic number, because the mean of its divisors is an integer number (2889214920).

Almost surely, 211544296957 is an apocalyptic number.

It is an amenable number.

11544296957 is a deficient number, since it is larger than the sum of its proper divisors (12562723).

11544296957 is an equidigital number, since it uses as much as digits as its factorization.

11544296957 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12562722.

The product of its digits is 2721600, while the sum is 53.

The spelling of 11544296957 in words is "eleven billion, five hundred forty-four million, two hundred ninety-six thousand, nine hundred fifty-seven".

Divisors: 1 919 12561803 11544296957